0=3x^2+14x-49

Solution for 0=3x^2+14x-49 equation:

0=3x^2+14x-49

We move all terms to the left:

0-(3x^2+14x-49)=0

We add all the numbers together, and all the variables

-(3x^2+14x-49)=0

We get rid of parentheses

-3x^2-14x+49=0

a = -3; b = -14; c = +49;
Δ = b2-4ac
Δ = -142-4·(-3)·49
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-28}{2*-3}=\frac{-14}{-6}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+28}{2*-3}=\frac{42}{-6}
=-7
$